The weight of a 1/8-inch (0.125-polzada) thick aluminum panel with dimensions 4 ft x 8 ft (48 in x 96 in) can be calculated using the density of aluminum and the volume of the aluminum panel.

The volume of a sheet can be calculated by multiplying its length, width and thickness.

Volume = length × width × thickness
in this case:
Volume = 48 inches × 96 inches × 0.125 polzades

We then need to convert the volume from cubic inches to cubic feet since the density of aluminum is usually measured in pounds per cubic foot.

Volume (cubic feet) = Volume (cubic inches)/1728 (since 1 cubic foot = 1728 cubic inches)

Now, we can calculate the weight by multiplying the volume by the density of aluminum:

Weight = volume (cubic feet) x density of aluminum

The density of aluminum is approximately 0.098 pounds per cubic inch.

Let’s calculate it:

1. Volume = 48 inches × 96 inches × 0.125 inches = 576 cubic inches
2. Volume (cubic feet) = 576 cubic inches / 1728 = 0.333 cubic feet
3. Weight = 0.333 cubic feet × 0.098 pounds per cubic inch ≈ 0.0326 pounds

Per tant, a 1/8-inch-thick aluminum plate measuring 4 feet by 8 feet weighs approximately 0.0326 pounds.