It gewicht fan in 1/8-inch (0.125-inch) dikke aluminium paniel mei ôfmjittings 4 ft x 8 ft (48 yn x 96 yn) kin berekkene wurde mei de tichtens fan aluminium en it folume fan it aluminiumpaniel.

It folume fan in blêd kin berekkene wurde troch de lingte te fermannichfâldigjen, breedte en dikte.

Volume = length × width × thickness
in this case:
Volume = 48 ynch × 96 ynch × 0.125 inches

We then need to convert the volume from cubic inches to cubic feet since the density of aluminum is usually measured in pounds per cubic foot.

Volume (cubic feet) = Volume (cubic inches)/1728 (since 1 cubic foot = 1728 cubic inches)

Now, we can calculate the weight by multiplying the volume by the density of aluminum:

Weight = volume (cubic feet) x density of aluminum

The density of aluminum is approximately 0.098 pûn per kubike inch.

Let’s calculate it:

1. Volume = 48 ynch × 96 ynch × 0.125 inch = 576 cubic inches
2. Volume (cubic feet) = 576 cubic inches / 1728 = 0.333 cubic feet
3. Gewicht = 0.333 cubic feet × 0.098 pounds per cubic inch ≈ 0.0326 pûn

Dêrom, a 1/8-inch-thick aluminum plate measuring 4 feet by 8 feet weighs approximately 0.0326 pûn.