Il-piż ta '1/8-pulzier (0.125-pulzier) pannell tal-aluminju oħxon b'dimensjonijiet 4 pied x 8 pied (48 f'x 96 fi) jista 'jiġi kkalkulat bl-użu tad-densità tal-aluminju u l-volum tal-pannell tal-aluminju.

Il-volum ta 'folja jista' jiġi kkalkulat billi timmultiplika t-tul tagħha, wisa 'u ħxuna.

Volume = length × width × thickness
in this case:
Volum = 48 pulzieri × 96 pulzieri × 0.125 pulzieri

We then need to convert the volume from cubic inches to cubic feet since the density of aluminum is usually measured in pounds per cubic foot.

Volume (cubic feet) = Volume (cubic inches)/1728 (since 1 cubic foot = 1728 cubic inches)

Now, we can calculate the weight by multiplying the volume by the density of aluminum:

Weight = volume (cubic feet) x density of aluminum

The density of aluminum is approximately 0.098 pounds per cubic inch.

Let’s calculate it:

1. Volum = 48 pulzieri × 96 pulzieri × 0.125 inches = 576 cubic inches
2. Volume (cubic feet) = 576 cubic inches / 1728 = 0.333 cubic feet
3. Weight = 0.333 cubic feet × 0.098 pounds per cubic inch ≈ 0.0326 pounds

Għalhekk, a 1/8-inch-thick aluminum plate measuring 4 feet by 8 feet weighs approximately 0.0326 pounds.